FIND THE WHOLE NUMBER
ANSWER : (2^96-1)
SOLUTION :
let x=2^32;
so (2^32+1)=(x+1);
Given that (x+1) is divided by whole number.
in option d,
(2^96)=(2^32)^3=x^3;
(x^3+1)=(x+1)(x^2-(x*1)+1);
it is also divided by whole number because it has term (x+1) in it.

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